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//Example 2.19b
clc;
x1=[1,1,1,1]
x2=[2,2,2,2]
a=1
b=1
for n=1:length(x1)
x3(n)=a*x1(n)+b*x2(n)
end
for n=1:length(x1)
y1(n)=exp(x1(n))
y2(n)=exp(x2(n))
y3(n)=exp(x3(n))
end
for n=1:length(y1)
z(n)=a*y1(n)+b*y2(n)
end
count=0
for n=1:length(y1)
if(y3(n)==z(n))
count=count+1;
end
end
if(count==length(y3))
disp('It satisfy the superposition principle');
disp('THE GIVEN SYSTEM IS LINEAR ');
else
disp('It does not satisfy superposition principle ');
disp('THE GIVEN SYSTEM IS NON LINEAR');
end
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