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clc
d0=0.15; // m
d1=0.1; // m
Q=50/3600; // m^3/s
f=0.0052;
Rho=972;
a=%pi/4*((d0)^2-(d1)^2);
P=%pi*((d0)+(d1));
d_eq=4*a/P;
v=Q/a;
del_p_f=2*f*Rho*v^2/d_eq;
disp("the pressure drop due to friction per metre length of tube is found to be ")
disp(del_p_f)
disp("Nm^2/m")
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