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//variable initialization
h=(6.625*10^-34)/(2*%pi); //Planck's constant (joule-second)
c=3*10^8; //speed of light (meter/second)
lembda=2000; //Wavelength of the light (Å)
phi=4.2 //work function of aluminium surface (eV)
ch=12400 //constant (eV Å)
//(a) maximum kinetic energy of photoelectrons
Tmax=(ch/lembda)-phi; //maximum kinetic energy of photoelectrons (eV)
//(b) minimum kinetic energy of photoelectrons
Tmin=0
//(c) cut-off wavelength
lembda_cut=ch/phi; // cut-off wavelength (Å)
//(d) stopping potential
v=2 //stopping potential (volt)
printf("\n(a) Maximum kinetic energy of photoelectrons = %.0f eV\n(b) Minimum kinetic energy of photoelectrons = %.0f\n(c) Cut-off wavelength = %.0f Å\n(d) Stopping potential = %.0f volt",Tmax,Tmin,lembda_cut,v);
//Note: In book answer of cut_off wavelength is wrong
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