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disp("Part a");
th=0.01*10^(-2);
bdv=20/10^(-3);
v=bdv*th;
disp("the following potential differnce (in V) will puncture the sheet of paper");
disp(v);
disp("Part b");
v1=600;
bdv1=16*10^3;
th1=v1/bdv1;
disp("the minimum thickness (in mm) is"); disp(th1);
disp("Part c");
th2=5;
f=2
v2=250;
bdv2=f*v2/th2;
disp("the minimum breakdown voltage (in kV/mm) required is"); disp(bdv2);
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