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disp("Part a");
r=100;
p=2;
i=sqrt(p/r);
disp("the maximum current (in mA) that the resistor can handle is"); disp(i*10^3);
disp("Part b");
p1=50*10^(-3);
v=40;
r1=(v^2)/p1;
disp("the resistance (in kΩ) is"); disp(r1*10^(-3));
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