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vdc=14.5;
disp("Part a");
vm=%pi*vdc/3;
disp("the necessary r.m.s. output voltage (in V) from the alternator is"); disp(vm);
disp("Part b");
idc=30;
im=%pi*idc/3;
disp("the peak current (in A) throught the diodes is"); disp(im);
disp("Part c");
disp("the P.I.V. (in V) of the diodes is"); disp(vm);
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