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c=10*10^(-6);
r=5*10^3;
v=24;
disp("Part a");
t=r*c;
disp("the time constan (in ms) of the circuit i; disp(t*10^3)");
disp("Part b");
rate=v/t;
disp("the initial rate of rise of capacitor voltage (in V/s) is"); disp(rate);
disp("Part c");
t1=5*t;
disp("time taken (in ms) to reach 24 V is"); disp(t1*10^3);
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