620/CH13/EX13.6/example13_6.sce


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v=1.4;
i=50*10^(-6);
i1=30*10^(-6);
r=3000;
rz=v/i-r;
rx=v/i1-r-rz;
disp("The value of Rx (in kΩ) coresponding to 30 μA is"); disp(rx/1000);