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v1=10;
fsd1=0.03;
v2=5;
i1=50*10^(-6);
r1=20*10^3;
fsd2=0.02;
i2=10*10^(-6);
disp("Part a");
r=v2/i2-r1;
disp("The resistance (in kΩ) is"); disp(r/1000);
disp("Part b");
e1=fsd1*v1*100/v2;
e2=fsd2*i1*100/i2;
e=e1+e2;
disp("The maximum possible error is"); disp(e);