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//Problem 15.24: An instantaneous current, i = 250 sin w t mA flows through a pure resistance of 5 kohm. Find the power dissipated in the resistor.
//initializing the variables:
R = 5000; // in ohms
Imax = 0.250; // in Amperes
//calculation:
Irms = 0.707*Imax
P = Irms*Irms*R
printf("\n\n Result \n\n")
printf("\n Power, P = %.1f Watts",P)
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