605/CH8/EX8.9/8_9.sce


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I1=1
V1=14*I1
I2=-2/3*I1
h11=V1/I1
h21=I2/I1
V2=9*I2
V1=6*I2
h12=V1/V2
h22=I2/V2
A=[h11,h12;h21,h22]
printf("\nA=")
disp(A)