605/CH13/EX13.1/13_1.sce


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P=10000
V=1000
W1=4*%pi*10^6
Wc=2*%pi*10^8
a=P/V^2
printf("\na=%.2f",a)
//(b)=
A=1000+2*225+2*150+2*75
peak_power=a*A^2
printf("\nA=%.0f V\npeak_power=%.0f W",A,peak_power)