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clear;
clc;
printf("\t Example 7.2\n");
//part(i)
a1=229.7; //solubility at 60 degree
a2=174.7; //solubility at 60 degree
t1=68; // percentage of sodium nitrate
t2=30.34;
x1=a1/329.7 *100; //percentage of saturated solution at 50 degree
tw=(t1/32)/(x1/t2); //the percentage saturation
printf("\nthe percentage saturation is :%f percent",tw*100);
//part(ii)
//let x be the weight of Cesium chloride crystal formed after crystallisation
x=poly([0],'x'); //calc. x the weight of crystal
t=roots(1000*.68-(x+(1000-x)*174.7/274.7));
printf("\n the weight of CaCl2 crystal formed after crystallisation :%f kg",t);
//part(iii)
yield=t/680; //yield = weight of CaCl2 crystal formed/weight of CaCl2
printf("\n the percentage yield of Cesium chloride is:%f percent",yield*100);
//end
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