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clear;
clc;
printf("\t Example 6_5_c\n");
//part(iii)
//let us choose the consistency of 11 and 13 readings
Xbar=0; //equillibrium moisture content
Ls=4.12; //mass of bone dry solid ais the drying surface
A=1; //both upper surafce and lower surface are exposed
Nc=0.19; //in kg/m^2*hr
X1=.098; //moisture content on dry basis intially
Xcr=.11; //kg moisture per kg dry solid
X2=0.074; //moisture content on dry basis finally
tfall=(Ls/(A*Nc))*((Xcr-Xbar)*log((X1-Xbar)/(X2-Xbar)));
printf("\n from this data we get time as :%f hour",tfall);
printf("\n the actual time is 0.8 hours");
//end
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