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clear;
clc;
printf("\t Example 5.4\n");
//part(i)
pa=13.3; //pressure in kpa
pa2=20.6; //vapour pressure at 60 degree
pt=106.6 //total pressure in kpa
y=pa/(pt-pa); //absolute molal humidity
y_bar=y*(18/28.84); //relative humidity
printf("\n absolute humidity of mixture :%f kg water-vapour/kg dry air",y_bar);
//part(ii)
mf=pa/pt; //mole fraction
printf("\n the mole fraction is :%f",mf);
//part(iii)
vf=mf; //volume fraction
printf("\n the volume fraction is :%f",vf);
//part(iv)
Ma=18; //molecular weight
Mb=28.84; //molecular weight
Tg=60; //temperature of mixture
rh=(pa/pa2)*100; //relative humidity in pecentage
printf("\n we get relative humidity as as :%f percent",rh);
//part(v)
VH=8315*[(1/Mb)+(y_bar/Ma)]*[(Tg+273)/pt]*10^-3; //humid volume in m^3mixture/kg of dry air
x=y_bar/VH; //g water/m^3 mixture
printf("\n we get x i.e. gwater/m^3 mixture as :%f ",x*1000);
//end
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