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clear;
clc;
printf("\t Example 5.2\n");
//dry bulb temperature=25 and wet bulb temperature=22
Tg=25; //dry bulb temperature=50
To=0; //refrence temperature in degree celcius
Mb=28.84; //average molecular weight of air
Ma=18; //average molecular weight of water
//part(i)
hum=.0145 //0.0145 kg of water/kg of dry air
printf("\n the saturation humidity(from chart) is :%f percent",hum);
//part(ii)
humper=57; //humidity percentage
printf("\n the percentage humidity is \t\t:%f percent",humper);
//part(iii)
pt=1; //total pressure in atm
sathum=0.0255; //molal humidity =pa/(pt-pa)
pa1=sathum*pt*(28.84/18)/(1+(sathum*(28.84/18)));
//the vopour pressure of water(steam tables)at 25 = .0393*10^5 N/m^2
pt=1; //total pressure in atm
molhum=0.0145; //molal humidity =pa/(pt-pa)
pa2=molhum*pt*(28.84/18)/(1+(molhum*pt*(28.84/18)));
//the vopour pressure of water(steam tables)at 25 = .0393*10^5 N/m^2
relhum=(pa2/pa1)*100; //percentage relative humidity =partial pressure/vapour pressure
printf("\n the percentage relative humidity is \t :%f ",relhum);
//part(iv)
dewpoint=19.5; //dew point temperature in degree celcius
printf("\n the dew point temperature \t :%f degree celcius",dewpoint);
//part(v)
Ca=1005;
Cb=1884;
ybar=.0145; // humidity inkg water /kg dry air
Cs=Ca+Cb*ybar; //humid heat in j/kg dry air degree celcius
d=2502300; //latent heat in j/kg
H=Cs*(Tg-0)+ybar*d; //enthalpy for refrence temperature of 0 degree
printf("\n we get Humid heat H as \t :%f j/kg",H);
//the actual answer is 62091.3 bt in book it is given 65188.25(calculation mistake in book)
//end
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