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clear;
clc;
printf("\t Example 2.20\n");
//this is the case of equimolar counter diffusion as the latent heat of vaporisation are very close to each other
T=(360); //temperature in kelvin
pt=372.4/760; //total pressure in atm
R=82.06; //universal gas constant
Dab=0.0506; //diffusion coefficient in cm^2/s
z=0.254; //gas layer thickness in cm
vp=368/760; //vapour pressure of toluene in atm
xtol=.3; //mole fractoin of toluene in atm
pb1=xtol*vp; //partial pressure of toluene
//since pb1 is .045263 bt in book it is rounded to 0.145
pb2=xtol*pt; //parial pressure of toluene in vapour phase
Na=Dab*(pb1-pb2)/(z*R*T); //diffusion flux
printf("\n the diffusion flux of a mixture of benzene and toluene %f*10^-8 gmol/cm^2*s\n",Na/10^-8);
printf("\nthe negative sign indicates that the toluene is getting transferred from gas phase to liquid phase(hence the transfer of benzene is from liquid to gas phase)")
//end
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