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clear;
clc;
printf("\t Example 2.16\n");
ya2=0.1; //molefraction at pos.2
ya1=0.8; //molefraction at pos.1
T=(370); //temperature in kelvin
pt=1*1.013*10^5; //total pressure in pascal
z=0.1*10^-3; //gas film thickness in m
Dab=.15*10^-2; //diffusion coefficient in m^2/s
R=8314; //universal gas constant
Area=10; //area of the film is 10m^2
//alcohol is being absorbed infrom amixture of alcohol vapour and water vapour by means of non-volatile solvent in which alcohol is soluble bt water is not
//for gase Dab=T^3/2
//Dab1/Dab2=(T1/T2)^3/2
T2=370; //final temperature in kelvin
T1=298; //initial temperature in kelvin
Dab1=.15*10^-2; //initial diffusion coefficient
Dab2=((T2/T1)^(3/2))*Dab1; //final diffusion coefficient
Na=Dab2*pt*log((1-ya2)/(1-ya1))/(z*R*T); //diffusion flux in kmol/m^2*s
rate=Na*3600*46*Area; //rate of diffusion of alcohol-water vapour in kg/hour
printf("\n rate of diffusion of alcohol-water vapour :%f *10^6 kg/hour ",rate/10^6);
//end
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