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//(12.1) The molar analysis of the gaseous products of combustion of a certain hydrocarbon fuel is CO2, 0.08; H2O, 0.11; O2, 0.07; N2, 0.74. (a) Determine the apparent molecular weight of the mixture. (b) Determine the composition in terms of mass fractions (gravimetric analysis).
//solution
//variable initialization
n1 = .08 // mole fraction of CO2
n2 = .11 // mole fraction of H2O
n3 = .07 //mole fraction of O2
n4 = .74 //mole fraction of N2
//part(a)
M1 = 44 //molar mass of CO2 in kg/kmol
M2 = 18 //molar mass of H2O in kg/kmol
M3 = 32 //molar mass of O2 in kg/kmol
M4 = 28 //molar mass of N2 in kg/kmol
M = M1*n1 + M2*n2 + M3*n3 + M4*n4 //in kg/kmol
printf('the apparent molecular weight of the mixture in kg/kmol is: %f',M)
//part(b)
mf1 = (M1*n1/M)*100 //mass fraction of CO2 in percentage
mf2 = (M2*n2/M)*100 //mass fraction of H2O in percentage
mf3 = (M3*n3/M)*100 //mass fraction of O2 in percentage
mf4 = (M4*n4/M)*100 //mass fraction of N2 in percentage
printf('\n\nthe mass fraction of CO2 in percentage is: %f',mf1)
printf('\nthe mass fraction of H2O in percentage is: %f',mf2)
printf('\nthe mass fraction of O2 in percentage is: %f',mf3)
printf('\nthe mass fraction of N2 in percentage is: %f',mf4)
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