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clc
W=150; //kJ
V1=0.6; //m^3
// p=8-4*V
// W=integration of p*dV from V1 to V2
// Solving above equation we get
V2=0.354; //m^3
disp("Final volume =")
disp(V2)
disp("m^3")
p2=8-4*V2;
disp("Final pressure =")
disp(p2)
disp("bar")
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