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//Example 11.16
clear;
clc;
printf("\tExample 11.16\n");
//Mole fractions
xf=[0.40 0.35 0.25];
xd=[0.534 0.453 0.013];
xw=[0 0.04 0.96];
//Amount of feed, product, bottom in kmol
F=[40 35 25];
D=[40 34 1];
W=[0 1 24];
//roots of equation
theta=[1.15 1.17];
//relative volatility
alpha=[2.7 2.22 1];
//Underwoods 1st equation for q=1
sums=[0 0];
for i=1:2
for j=1:3
sums(i)=sums(i)+(alpha(j)*xf(j)/(alpha(j)-theta(i)));
end
end
printf("\nFrom Underwoods 1st eq\n");
printf("The value of 1-q at theta = 1.15 and 1.17 are");
disp(sums);
//Underwoods 2nd equation for minimum reflux ratio
sum2=0;
for l=1:3
sum2=sum2+(alpha(l)*xd(l)/(alpha(l)-theta(2)));
end
Rm=sum2-1;
printf("\nMinimum Reflux ratio is %.3f\n",Rm);
//End
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