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//Suitable material required
clear;
clc;
printf("\tExample 21.3\n");
R=0.05;
n=poly([0],'x');
//R = (ns-1/ns+1)^2 leading to the equation
// 0.95ns^2-2.1ns+0.95 = 0
//HencE
ns=roots((0.95*n^2)-(2.1*n)+0.95);
disp(ns,'The values of ns are: ");
printf("Thus, soda-lime glass, Pyrex glass, and polyprop would be suitable for this application.");
//End
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