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//exmple 6.1
clc;
clear;
//a=input("enter the first 8 bit number :");
//b=input("enter the second 8 bit number :");
a=01010111; // taking given inputs
b=00110101;
for i=1:8
a1(i)=modulo(a,10);
a=a/10;
a=round(a);
b1(i)=modulo(b,10);
b=b/10;
b=round(b);
end
car(1)=0;
for i=1:8 // adding both the inputs (binary addition)
c1(i)=car(i)+a1(i)+ b1(i);
if c1(i)== 2 then
car(i+1)= 1;
c1(i)=0;
elseif c1(i)==3 then
car(i+1)= 1;
c1(i)=1;
else
car(i+1)=0;
end
end
c1(9)=car(9);
re=0;
format('v',18);
for i=1:9
re=re+(c1(i)*(10^(i-1)))
end
printf('The sum of given two binary numbers is %d\n',re );
q=1;
b=0;
f=0;
a=re;
while(a>0) // converting the result to a hexadecimal no
r=modulo(a,10);
b(1,q)=r;
a=a/10;
a=floor(a);
q=q+1;
end
for m=1:q-1
c=m-1;
f = f + b(1,m)*(2^c);
end
hex=dec2hex(f);
printf(' The sum in hexadecimal notation is %s \n',hex); //displaying result
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