blob: 4cf04244e7f2388a94ab97f12b375a004add410a (
plain)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
|
clear ;
clc;
// Example 8.2
printf('Example 8.2\n\n');
// Page no. 199
// Solution Fig. E8.2b
F_O2 = 0.21 ;// fraction of O2 in feed(F)
F_N2 = 0.79 ;// fraction of N2 in feed(F)
P_O2 = 0.25 ;// fraction of O2 in product(P)
P_N2 = 0.75 ;// fraction of N2 in product(P)
F = 100 ;// Feed - [g mol]
w = 0.80 ;// Fraction of waste
W = w*F ;// Waste -[g mol]
// By analysis for degree of freedom , DOF comes to be zero
P = F - W ;// By overall balance - [g mol]
W_O2 = (F_O2*F - P*P_O2)/100 ;// Fraction of O2 in waste stream by O2 balance
W_N2 = (W - W_O2*100)/100 ;//Fraction of N2 in waste stream
printf('Composition of Waste Stream\n' );
printf('\n Component Fraction in waste stream\n' );
printf(' O2 %.2f\n',W_O2 );
printf(' N2 %.2f\n',W_N2 );
|
