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clear ;
clc;
// Example 24.2
printf('Example 24.2\n\n');
//page no. 725
// Solution
printf('Table to carry out degree of freedom analysis:\n');
// Number of variables involved
printf('\nI. Number of variables involved.\n');
printf('\n For materials:\n');
printf(' Hot gas : 4 component flows, T, and p 6 \n');
printf(' Cool gas : 4 component flows, T, and p 6\n');
printf(' Water in : 1 component flow, T, and p 3\n');
printf(' Water out : 1 component flow, T, and p 3\n');
printf('\n Energy:\n');
printf(' Q and W 2 \n');
printf(' H,KE and PE associated with each stream flow 12 \n');
printf('\_______________________________________________________________________\n');
printf(' Total 32\n');
printf('\n\nII. Number of equations and specifications.\n');
printf('\n Specified values:\n');
printf(' Hot gas : 4 component flows, T, and p 6 \n');
printf(' Cool gas : T, and p 2\n');
printf(' Water in : T, and p 2\n');
printf(' Water out : T, and p 2\n');
printf('\n Specified in the energy balance:\n');
printf(' Q and W 2 \n');
printf(' KE and PE associated with each of 4 stream flow 8 \n');
printf('\n Material balance: \n');
printf(' 4 species balances plus water 5 \n');
printf('\n Energy balance: 1\n');
printf('\n H in each stream is a function of specified T and p 4\n');
printf('\_______________________________________________________________________\n');
printf(' Total 32\n');
printf('\n Therefore, by analysing the above table it is clear that degrees of freedom of system is (32 - 32) = 0 \n');
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