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clear ;
clc;
// Example 13.3
printf('Example 13.3\n\n');
// Page No.406
// Solution
m_CO2 = 88 ;// Mass of CO2-[lb]
mol_wt_CO2 = 44 ;// Molecular mass of 1 lb mol CO2 -[lb]
mol_V = 359 ; // Molar volume-[cubic feet]
// State 1-standard condition
P1 = 33.91 ; // Pressure -[ft of water]
T1 = 273 ;// Temperature-[K]
// State 2
P2 = 32.2 ;// Pressure -[ft of water]
Tc = 15 ;// Temperature-[degree C]
T2 = Tc+273 ;// Temperature-[K]
// Use eqn. 13.2 to get final volume
V1 = (m_CO2 * mol_V) / (mol_wt_CO2);
V2 = (V1 * T2 * P1) / (T1 * P2);
printf('The volume occupied 88 lb of CO2 at given condition is %.0f cubic feet.',V2);
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