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clear ;
clc;
// Example 11.1
printf('Example 11.1\n\n');
// Page no. 311
// Solution
// Composition of each stream
w_A1 = 1 ;//concentration of A in 1
w_B2 = 1 ;// concentration of B in 2
w_A3 = 0.8 ;// concentration of A in 3
w_B3 = 0.2 ;// concentration of B in 3
w_C4 = 1 ;// concentration of C in 4
w_A5 = 0.571 ;//concentration of A in 5
w_B5 = 0.143 ;//concentration of B in 5
w_C5 = 0.286 ;//concentration of C in 5
w_D6 = 1;// concentration of D in 6
w_A7 = 0.714 ;// concentration of A in 7
w_B7 = 0.286 ;// concentration of B in 7
w_B8 = 0.333 ;//concentration of B in 8
w_C8 = .667 ;//concentration of C in 8
us1 = 2 ;// Species involved in unit 1
us2 = 3 ;// Species involved in unit 2
us3 = 4 ;// Species involved in unit 3
total_sp = us1+us2+us3 ;// Total species in system
// Element balance of all systems
printf('Number of possible equations are 9, they are as follows- \n');
printf(' Subsystem 1\n');
printf(' A: F1*w_A1+F2*0 = F3*w_A3 (a)\n');
printf(' B:F1*0 + F2*w_B2 = F3*w_B3 (b)\n');
printf(' Subsystem 2\n');
printf(' A: F3*w_A3+F4*0 = F5*w_A5 (c)\n');
printf(' B:F3*w_B3 + F4*0 = F5*w_B5 (d)\n');
printf(' C: F3*0+F4*w_C4 = F5*w_C5 (e)\n');
printf(' Subsystem 3\n');
printf(' A: F5*w_A5+F6*0 = F7*w_A7+F8*0 (f)\n');
printf(' B:F5*w_B5 + F6*0 = F7*0+F8*w_B8 (g)\n');
printf(' C: F5*w_C5+F6*0 = F7*0+F8*w_C8 (h)\n');
printf(' D:F5*w_C5+F6*0 = F7*0+F8*w_C8 (i)\n');
printf('\n The above equations do not form a unique set\n');
// By inspection we can see that only 7 equations are independent
//Independent Equations are:
// Subsystem 1
//A: F1*w_A1+F2*0 = F3*w_A3 (a)
//B:F1*0 + F2*w_B2 = F3*w_B3 (b)
//Subsystem 2
//A: F3*w_A3+F4*0 = F5*w_A5 (c)
// C: F3*0+F4*w_C4 = F5*w_C5 (e)
// Subsystem 3
//A: F5*w_A5+F6*0 = F7*w_A7+F8*0 (f)
//B:F5*w_B5 + F6*0 = F7*0+F8*w_B8 (g)
//D:F5*w_C5+F6*0 = F7*0+F8*w_C8 (i)
printf('\n Number of independent equations are 7 \n');
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