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//Electric Power Generation, Transmission and Distribution by S.N.Singh
//Publisher:PHI Learning Private Limited
//Year: 2012 ; Edition - 2
//Example 3.6
//Scilab Version : 6.0.0 ; OS : Windows
clc;
clear;
V=240; //Three phase supply voltage in Volts
Rl=20; //Load Resistance in Ohms
Vbase=240; //Three phase Base voltage in Volts
VAbase=10*10^3; //Base voltage in kVA
Vpu=V/Vbase; //Voltage in p.u.
Zbase=(Vbase^2/VAbase); //Base Impedance in Ohms
Zpu=Rl/Zbase; //Load Impedance in p.u.
Ibase=VAbase/((nthroot(3,2))*Vbase); //Base Current in Amps
Ipu=Vpu/Zpu; //Current drawn in p.u.
Ia=Ipu*Ibase; //Current drawn in Amps
P=Vpu*Ipu; //Power drawn in p.u.
Pt=(Ipu*VAbase)/1000; //Power drawn in kW
printf("\nCurrent drawn in amps %.2f A",Ia);
printf("\nPer unit value of current referred to the load side %.3f p.u",Ipu);
printf("\nPower drawn in kilo watts %.3f kW",Pt);
printf("\nPer unit value of Power referred to the load side %.3f p.u",P);
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