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//Differential screw jack
//pitch
pA=10 //mm
pB=5 //mm
//lever arm length
R=500 //mm
VR=(2*%pi*R)/(pA-pB)
P=185 //N
W=15000 //N
MA=W/P
eta=MA*100/VR //percent
//let the law of machine be P=m*W+C
//from first case 185=m*15000+C
//from second case 585=m*50000+C
//solving we get
m=4/350
C=185-(m*15000) //N
printf("Law of machine is P=%.4f*W+%0.2d ",m,C)
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