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//moving weight
//refer fig.17.6 (a),(b)and(c)
//first method
//For 2000 N block
W1=2000 //N
mu=0.2
N1=W1*cosd(30) //N
F1=mu*N1 //N
//For 1800N block
W2=1800 //N
N2=W2*cosd(60) //N
F2=mu*N2 //N
//Let T be the tension in the chord
u=0
v=9.81 //m/sec
//applying impulse momentum equation for the 2000 N block in upward direction parallel to the plane
//(T-1346.41)*t=2000
//Applying impulse momentum equation for 1800 N block
T=1363.48 //N
//Thus
t=117.11 //sec
printf("\nBy first method-\nT=%.2d N\nt=%.2d sec",T,t)
//second method
//Writing impulse momentum equation in the direction of motion
t1=117.11 //sec
//To find tension in the chord, consider impulse momentum equation of any block
T1=1363.48 //N
printf("\nBy second method-\nt=%.3f sec\nT=%.3f N",t1,T1)
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