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//Block on inclined plane
//refer fig. 17.5
theta=atand(5/12) //degree
N=130*cosd(theta) //N
mu=0.3
F=mu*N //N
//Force down the plane
R=130*sind(theta)-36 //N
u=2.4 //m/sec
//v is final velocity
t=5 //sec
//applying impulse momentum equation
v=((14*5*9.81)/(130))+2.4 //m/sec
printf("\nv=%.3f m/sec",v)
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