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//cage and mine shaft
//t is time during which stone is in motion
//s=(9.81*t^2)/2
//consider motion of cage
//t1 be the time taken to travel first 30 m
a=0.6  //m/sec^2
t1=10  //sec
//When the stone strikes 
//s=(0.6*(t+10)^2)/2  
//solving
t=3.286  //sec
s=(9.81*3.286^2)/2  //m
printf("\nt=%.2f sec\ns=%.2f m",t,s)