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// Book - Power System: Analysis & Design 5th Edition
// Authors - J. Duncan Glover, Mulukutla S. Sharma, Thomas J. Overbye
// Chapter - 4 : Example 4.1
// Scilab Version 6.0.0 : OS - Windows
clc;
clear;
S = 12; // Number of strands
Sd = 0.1328; // Diameter of the Strand
R = 0.302; // Resistance at 50 Deg Celcius in Ohm/miles
f = 60; // Frequency
T = 241.5; // Temperature Constant of Hard Drawn Copper
T1 = 20; // Temperature in Degree Celcius
T2 = 50; // Temperature in Degree Celcius
T3 = 25; // Temperature in Degree Celcius
R60T2 = 0.303; // Resistance at 60 Hz with 50 degree celcius From the Table A.3
R60T3 = 0.278; // Resistance at 60 Hz with 25 degree celcius From the Table A.3
RdcT3 = 0.276; // DC Resistace at 25 Degree Celcius
Sd = (0.1328*1000); // Coverting Strand Diameter from inch to mil/inch
A = 12*Sd^2 ; // Cross Sectional Area of the 12 strand Conductors in cmil
pT1 = 10.66; // Resistivity at Temperature T1
pT2 = pT1*((T2+T)/(T1+T)); // Resistivity at 50 deg Celcius in Ohm-cmil/ft
L = (5280*1.02); // Length of the Conductor in ft
RdcT2 = (pT2*L)/A; // DC Resistance at 50 Degree celcius in Ohm/miles
IncR50 = (R60T2)/(RdcT2); // Percentage Increase in Resistace for 50 degree celcius at 60 Hz Versus dc
IncR25 = (R60T3)/(RdcT3); // Percentage Increase in Resistace for 25 degree celcius at 60 Hz Versus dc
printf('\n Cross Sectional Area of the 12 strand Conductor is (A) = %0.0f cmil',A);
printf('\n DC Resistance at 50 Degree celcius is (RdcT2) = %0.3f Ohm/mi',RdcT2);
printf('\n From table A.3, ratio at 50 Degree celcius is (IncR50) = %0.3f ',IncR50);
printf('\n From table A.3, ratio at 25 Degree celcius is (IncR25) = %0.3f ',IncR25);
printf('\n The 60 Hz resistance of the conductor is about %.2f to %.2f percentage higher than DC resistance',(IncR50-1)*100,(IncR25-1)*100);
//There is a small variation in the result since the value of cross sectional area which is actually 211630 is rounded off to 211600 in the book.
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