blob: 0d15d7ff992f8da5cc60b7d8bc389f405fb16541 (
plain)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
|
//===========================================================================
//chapter 6 example 26
clc;
clear all;
//variable declaration
KT = 199; //turn ration
Is = 5; //secondary current in A
Im = 7; //magnetising component of exciting current in A
Ie = 4; //cross-loss component of exciting current in A
delta =0;
//calculations
KN = 1000/5 //nominal ratio
alpha =atan(Ie/Im) //angle in °
alpha1 = (alpha*180)/%pi
theta = delta+(((acos(0.8))*180)/%pi) //from figure taken the value of gamma
z = cos((theta*%pi)/180)
z1 = sin(((theta)*%pi)/180)
Kc = KT+(((Ie*z)+(Im*z1))/Ie) //actual current in A
e = ((Kn-Kc)/Kc)*100 //ratio error
b =(180/%pi)*(((Im*z)-(Ie*z1))/(KT*Is))
theta1 = delta-(((acos(0.8))*180)/%pi) //from figure taken the value of gamma
z11 = cos((theta1*%pi)/180)
z12 = sin(((theta1*%pi)/180))
Kc1 = KT+(((Ie*z11)+(Im*z12))/Is) //actual current in A
e1 = ((Kn-Kc1)/Kc1)*100 //ratio error
b1 =(180/%pi)*(((Im*z11)-(Ie*z12))/(KT*Is))
//result
mprintf("ratio error = %3.2f percentage",e);
mprintf("\nphase angle error = %3.1f °",b);
mprintf("\nratio error = %3.2f percentage",e1);
mprintf("\nphase angle error = %3.2f percentage°",b1);
|
