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//===========================================================================
//chapter 6 example 17
clc;clear all;
//variable declaration
Tp = 1; //number of turns in primary
KT = 200; //turns ratio
Is = 5; //secondary current in A
Rs = 1.5; //secondary burden in Ω
f = 50; //frequency in Hz
L =1.5; //iron loss in Watts
Ie = 40; //current in A
//calculaations
Ts = KT*Tp; //number of turns in secondary
Vs = Is*Rs; //secondary voltage in V
phimax = Vs/(4.44*f*Ts); //flux inn the core in mWb
Il = L/(Vs); //iron-loss in the secondary side in A
Ip = KT*Il; //iron-loss current in primary side in A
x =(KT*Is)+Ie;
e = ((-Ie/((x))))*100; //ratio error in %
//result
mprintf("flux in the core = %3.3e percentage mWb",(phimax*10^3));
mprintf("\nratio error = %3.4f percentage",e);
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