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//===========================================================================
//chapter 5 example 34
clc;
clear all;
//variable declaration
e0 =8.854*10^-12;
d =0.05;
er = 1;
a = 0.25;
V1 = 12000; //voltage in V
V2 = 32000; //voltage in V
//calculations
//x-x0 = (1/2)*((V^2)/k)*(dc/dx)
//C =(2*e0*er*A)/d
//dC =(2*e0*er*a*x)/d
// y = dC/dx = (2*e0*er*a)/d
y = (2*e0*er*a)/d;
X1 = 0.25/4;
// A =x1+x01 = (1/2)*((V1^2)/k)*(dc/dx)
X2 = 0.25/2;
//B = x2+x01 = (1/2)*((V2^2)/k)*(dc/dx)
//C = B/A =(V2/V1)^2
C = (V2/V1)^2;
x01 = (X2-(C*X1))/(1-C);
k = ((1/2)*((V1^2))*(y))/(X1-x01);
X3 = (3/4)*0.25;
V = sqrt(((X3-x01)*2*k)/y); //voltage in V
//result
mprintf("voltage required to pull the plate three quarte way in = %3.3f KV",(V*10^-3));
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