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//===================================================================
//Chapter 12 Example 2
clc;
clear all;
//variable declaration
Z1 = 1000; //resistance of arm in Ω
Z2 = 500; //resistance of arm in Ω
Z3 = 1000; //resistance of arm in Ω
Z4 = 509.9; //resistance of arm in Ω
ZX4 =100+500*%i;
theta1 = -90; //angle in °
theta2 = 0; //angle in °
theta3 = 0; //angle in °
theta4 = -90; //angle in °
theta41 = 78.69;
//calculations
thetax = theta1+theta41;
thetay = theta2+theta3;
x = Z2*Z3;
//Z1*Z4 =Z2*Z3
//1/Z1 = A = Z4/Z2*Z3 = Z4/x
A = ZX4/x;
//1/Z1 = 1/R1 +(w*C1)*%i
Zx3 = (Z1*Z4)/Z2;
thetax3 = theta1+theta41-theta2;
Z3 = (Zx3*cos(thetax3*%pi/180))+(Zx3*sin(thetax3*%pi/180));
//result
mprintf("thetax = %3.2f °",thetax);
mprintf("\nthetax = %3.2f °",thetay);
mprintf("\nbalance can be restored by modifying the circuit so asto satisfy the phase angle condition");
mprintf("\ncomparing equations 1 and 2 R1 = %3.2f",1/real(A));
mprintf("\ncomparing equations 1 and 2 1/w*C1 = %3.2e",imag(A));
mprintf("\n1/w*C1 is already equal to 1000 Ω so the bridge can be easily balanced by adding 5000 Ω accross capacitor in arm 1");
mprintf("\nsince R3 is already of 1000 Ω so the bridge can be easily balanced by adding capacitance 200 Ω in series across in arm 3");
mprintf("Note:there was a possibility that with the addition of resistance R1 in armm 1 as first option or with teh addition of capacitance C3 in arm 3");
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