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//
//
//Initilization of Variables
q_b=80 //N/mm**2 //Shear stress in Brass
q_s=100 //N/mm**2 //Shear stress in Steel
G_b=40*10**3 //N/mm**2
G_s=80*10**3
L_b=1000 //mm //Length of brass shaft
L_s=1200 //mm //Length of steel shaft
d1=80 //mm //Diameter of brass shaft
d2=60 //mm //Diameter of steel shaft
//Calculations
//Polar modulus of brass rod
J_b=%pi*32**-1*d1**4 //mm**4
//Polar modulus of steel rod
J_s=%pi*32**-1*d2**4 //mm**4
//Considering bras Rod:AB
T1=J_b*q_b*(d1*2**-1)**-1 //N-mm
//Considering Steel Rod:BC
T2=J_s*q_s*(d2*2**-1)**-1 //N-mm
//Max Torque that can be applied
T2
//Let theta_b and theta_s be the rotations in Brass and steel respectively
theta_b=T2*L_b*(G_b*J_b)**-1 //Radians
theta_s=T2*L_s*(G_s*J_s)**-1 //Radians
theta=theta_b+theta_s //Radians //Rotation of free end
//Result
printf("\n Total of free end is %0.3f Radians",theta)
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