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clear
//
//
//Initilization of Variables
A_C=230*400 //mm //Area of column
D_s=12 //mm //Diameter of steel Bar
P=600*10**3 //N //Axial compression
//E_s*E_c=18.67
n=8 //number of steel Bars
//Calculations
A_s=%pi*4**-1*D_s**2*n //Area of steel //mm**2
A_c=A_C-A_s //mm**2 //Area of concrete
//From static Equilibrium condition
//P_s+P_c=600 .........(1)
//Now from compatibility Equation dell_l_s=dell_l_c we get,
//P_s*L*(A_s*E_s)**-1=P_c*L*(A_c*E_c)**-1
//Substituting values in above Equation we get
//P_s=0.1854*P_c
//Now Substituting value of P_s in Equation (1),we get
P_c=600*1.1854**-1
P_s=600-P_c
//Stress in steel
sigma_s=P_s*10**3*A_s**-1 //N/mm**2
//Stress in copper
sigma_c=P_c*10**3*A_c**-1 //N/mm**2
//Result
printf("\n Stresses Developed in Two material are:sigma_s %0.2f N/mm**2",sigma_s)
printf("\n :sigma_c %0.2f N/mm**2",sigma_c)
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