blob: e220de5383cfa14b4fba62841abaef8c0bc599b2 (
plain)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
|
clear
//
//A bar can develop a tensile force or a compressive force. Let the force developed be a compressive force S (push on the cylinder).
//variable declaration
W=10.0 //weight of Roller,KN
IL=7.0 //inclined loading at angle of 45°,KN
H=5.0 //Horizontal loading ,KN
theta=45.0*%pi/180 //angle of loading of IL
thetaS=30.0*%pi/180.0
//Since there are more than three forces in the system, Lami’s equations cannot be applied. Consider the components in horizontal and vertical directions.
//sum of vertical Fy & sum of horizontal forces Fx is zero
//Assume direction of Fx is right
//Assume direction of Fy is up
S=(-H+IL*cos(theta))/cos(thetaS)
printf("\n S= %0.3f N",S)
printf("\n Since the value of S is negative the force exerted by the bar is not a push, but it is pull (tensile force in bar) of magnitude %0.3f kN.",-S)
R=W+IL*sin(theta)-S*sin(thetaS)
printf("\n R= %0.3f kN",R)
|
