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//How much work must be done by a heat pump when the outdoor temperature is 5 dgree and minus 10 degree
//Example 5.3
clc;
clear;
q2=5000; //Amount of heat deliver by a pump in J
T2=295; //Temperature of house in K
T1=278; //Outdoor teperature in K
q1=abs(q2)*(T1/T2); //Amount of heat in J
w1=abs(q2)-q1; //Amount of work done by a heat pump when the outdoor temperature is 5 dgree in J
printf("(a)Amount of work done when the outdoor temperature is 5 dgree = %.0f J",w1);
T3=263; //Outdoor teperature in K
q1=abs(q2)*(T3/T2); //Amount of heat in J
w2=abs(q2)-q1; //Amount of work done by a heat pump in J
printf("\n(b)Amount of work done when the outdoor temperature is minus 10 degree = %.0f J",w2);
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