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//Calculate the value of change in Internal energy and change in Enthalpy for the combution of Benzoic acid
//Example 4.3
clc;
clear;
C=5267.8; //Effective heat capcity of bomb calorimeter plus water im J K^-1
T1=293.32; //Initial temperature in K
T2=295.37; //Final temperature in K
delT=T2-T1; //Change in teperature in K
M=122.12; //Molar mass of Benzoic acid in g mol^-1
m=0.4089; //Mass of sample of Benzoic acid in g
delU=-(C*delT*M)/(m*1000); //Change in Enternal enegy in kJ mol^-1
printf("Change in Enternal energy = %.0f kJ mol^-1",delU);(The answer vary due to round off error)
R=8.314; //Gas constant in J K^-1 mol^-1
T=T1; //Temperature in K
n1=7.5; //Number of moles of gas for reactants
n2=7; //Number of mole of gas for product
deln=n2-n1; //Change of moles gas for reaction
delH=delU+((R*T*deln)/1000); //Change in Enthalpy in kJ mol^-1
printf("\nChange in Enthalpy = %.0f kJ mol^-1",delH);
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