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//Example 23.6
Np=200;//Number of loops in the primary
Vp=120;//Primary voltage (V)
Vs=15;//Secondary voltage (V)
Ns=Np*Vs/Vp;//Number of loops in the secondary
printf('a.Number of loops in the secondary coil = %0.1f',Ns)
Is=16;//Current in the secondary coil (A)
Ip=Is*Ns/Np;//Current in the primary coil (A)
printf('\nb.Input current = %0.2f A',Ip)
//Openstax - College Physics
//Download for free at http://cnx.org/content/col11406/latest
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