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clear
//
//Initialisation
pf=0.75 //power factor
S=2000 //apparent power in VA
V=240 //Voltage in volts
//Calculation
apf=S*pf //active power
sin1=sqrt(1-(pf**2))
Q=S*sin1 //Reactive Power
I=S*V**-1 //Current
//Result
printf("\n Apparent Power, P = %d W",S)
printf("\n Active Power, P = %d W",apf)
printf("\n Reactive Power, Q = %d var",Q)
printf("\n Current I = %.2f A",I)
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