3835/CH4/EX4.29/Ex4_29.sce


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clear
//
//case a
l=0.25
f=50
v=230
r=2
c=1/(((2*3.14*f)**2)*l)
printf("\n c= %e  ",c)
//case b
i=v/r
printf("\n i= %0.1f  A",i)
//case c
vl=2*3.14*f*l*i
vc=i/(c*2*3.14*f)
q=(2*3.14*f*l)/(r)
printf("\n q")