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clear
//
v=120
V=200
//v=V(1-e^-5/2R)
//120=200*(1-e^-5/2R)
//applying log on both sides and solving we get R=2.72 Mohm
printf("\n R=2.72Mohm")
R=5
tc=10
//applying in the above eqn and solving lograthmically we get t=9.16
printf("\n t=9.16 sec")
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