3835/CH2/EX2.28/Ex2_28.sce


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clear
//
//req=[10+2+(5||15)]=15.75
//case a
c=0.4
req=15.75
s=-1/(c*req)
printf("\n natural frequency= %0.1f  secinverse",s)
//case b
tc=req*0.4 //time constant
printf("\n time constant= %0.1f  sec",tc)