3835/CH1/EX1.16/Ex1_16.sce


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clear
//
//given
dv=20 //dv/dt
c=25*(10**-6)
//case a
i=c*dv
printf("\n i= %e  A",i)
//case b
q=c*dv
printf("\n q= %e  C",q)
//case c
p=dv*i
printf("\n p= %e  W",p)
//case d
v=dv**2
wc=(c*v)/2
printf("\n wc= %e  J",wc)