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// Example 5_4
clc;funcprot(0);
// Given data
W=0.250;// hp
V=1.00;// quart of water
p_1=14.7;// psia
T_1=60.0;// °F
p_2=p_1;// psia
t=10;// min
c=1.00;// Btu/(lbm.R)
// Calculation
V=V*(1/4)*0.13368;// ft^3
v=0.01603;// ft^3/lbm
m=V/v;// lbm
Q_12bymc=0;
T_2=T_1+Q_12bymc-((-W*t*(1/60)*(2545))/(m*c));// °F
printf('\nThe temperature of the water when the machine is turned off,T_2=%3.0f°F',T_2)
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