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// Exa 7.3
clc;
clear;
// Given
N = 50; // No of turns of potentiometer per mm
Number_of_Resolution = 4; // No of resolutions of potentiometer
// Solution
Resolution = 1/N;
printf(' Resolution of potentiometer = %.3f mm \n',Resolution);
printf(' 4 resolutions of potentiometer with one rotation = %.1f mm \n',10^3*Resolution/Number_of_Resolution);
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